cas: 22465-48-1 — see every product listed under this CAS number, including other names
Hydroxocobalamin acetate 98% (CAS 22465-48-1) is a chemical reagent available from Chemat. Available pack sizes: 250mg, 1g, 5g. Offered by: Ambeed.
| brand | Ambeed |
|---|---|
| catalog number | A291290-250mg |
| cas | 22465-48-1 |
| size | 250mg |
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| brand | size | price | |
|---|---|---|---|
| Ambeed | 250mg | 531.69 Pln | |
| Ambeed | 1g | 1416.12 Pln | |
| Ambeed | 5g | 5465.62 Pln |
| purity | 98% |
|---|---|
| delivery time | 1-2 weeks |
| ambeed catalog no. | A291290 |
Acetic acid;cobalt;[(2R,3S,4R,5S)-5-(5,6-dimethylbenzimidazol-1-yl)-4-hydroxy-2-(hydroxymethyl)oxolan-3-yl] 1-[3-[(1R,2R,3R,5Z,7S,10Z,12S,13S,15Z,17S,18S,19R)-2,13,18-tris(2-amino-2-oxoethyl)-7,12,17-tris(3-amino-3-oxopropyl)-3,5,8,8,13,15,18,19-octamethyl-2,7,12,17-tetrahydro-1H-corrin-24-id-3-yl]propanoylamino]propan-2-yl phosphate (CAS 22465-48-1) is a chemical compound with the molecular formula C64H92CoN13O16P-2 and a molecular weight of 1389.4 g/mol. IUPAC name: acetic acid;cobalt;[(2R,3S,4R,5S)-5-(5,6-dimethylbenzimidazol-1-yl)-4-hydroxy-2-(hydroxymethyl)oxolan-3-yl] 1-[3-[(1R,2R,3R,5Z,7S,10Z,12S,13S,15Z,17S,18S,19R)-2,13,18-tris(2-amino-2-oxoethyl)-7,12,17-tris(3-amino-3-oxopropyl)-3,5,8,8,13,15,18,19-octamethyl-2,7,12,17-tetrahydro-1H-corrin-24-id-3-yl]propanoylamino]propan-2-yl phosphate. InChIKey: JEINOAHBVLNVDD-WYVZQNDMSA-L.
| Molecular formula | C64H92CoN13O16P-2 |
|---|---|
| Molecular weight | 1389.4 g/mol |
| IUPAC name | acetic acid;cobalt;[(2R,3S,4R,5S)-5-(5,6-dimethylbenzimidazol-1-yl)-4-hydroxy-2-(hydroxymethyl)oxolan-3-yl] 1-[3-[(1R,2R,3R,5Z,7S,10Z,12S,13S,15Z,17S,18S,19R)-2,13,18-tris(2-amino-2-oxoethyl)-7,12,17-tris(3-amino-3-oxopropyl)-3,5,8,8,13,15,18,19-octamethyl-2,7,12,17-tetrahydro-1H-corrin-24-id-3-yl]propanoylamino]propan-2-yl phosphate |
| InChIKey | JEINOAHBVLNVDD-WYVZQNDMSA-L |
| SMILES | CC1=CC2=C(C=C1C)N(C=N2)[C@@H]3[C@@H]([C@@H]([C@H](O3)CO)OP(=O)([O-])OC(C)CNC(=O)CC[C@@]4([C@H]([C@@H]5[C@]6([C@@]([C@@H](/C(=C(/C7=N/C(=C\C8=N/C(=C(\C4=N5)/C)/[C@H](C8(C)C)CCC(=O)N)/[C@H]([C@]7(C)CC(=O)N)CCC(=O)N)\C)/[N-]6)CCC(=O)N)(C)CC(=O)N)C)CC(=O)N)C)O.CC(=O)O.[Co] |
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