cas: 2102510-60-9 — see every product listed under this CAS number, including other names
ITDBR, EH-IDTBR 99% (CAS 2102510-60-9) is a chemical reagent available from Chemat. Available pack sizes: 50mg, 100mg, 250mg, 1g. Offered by: Ambeed.
| brand | Ambeed |
|---|---|
| catalog number | A1156261-50mg |
| cas | 2102510-60-9 |
| size | 50mg |
Ask us about this product — we're happy to help.
| brand | size | price | |
|---|---|---|---|
| Ambeed | 50mg | 2061.38 Pln | |
| Ambeed | 100mg | 3446.44 Pln | |
| Ambeed | 250mg | 5816.06 Pln | |
| Ambeed | 1g | 15567.13 Pln |
| purity | 99% |
|---|---|
| delivery time | 2-3 weeks |
| ambeed catalog no. | A1156261 |
(5Z)-3-ethyl-2-sulfanylidene-5-[[4-[9,9,18,18-tetrakis(2-ethylhexyl)-15-[7-[(Z)-(3-ethyl-4-oxo-2-sulfanylidene-1,3-thiazolidin-5-ylidene)methyl]-2,1,3-benzothiadiazol-4-yl]-5,14-dithiapentacyclo[10.6.0.03,10.04,8.013,17]octadeca-1(12),2,4(8),6,10,13(17),15-heptaen-6-yl]-2,1,3-benzothiadiazol-7-yl]methylidene]-1,3-thiazolidin-4-one (CAS 2102510-60-9) is a chemical compound with the molecular formula C72H88N6O2S8 and a molecular weight of 1326.0 g/mol. IUPAC name: (5Z)-3-ethyl-2-sulfanylidene-5-[[4-[9,9,18,18-tetrakis(2-ethylhexyl)-15-[7-[(Z)-(3-ethyl-4-oxo-2-sulfanylidene-1,3-thiazolidin-5-ylidene)methyl]-2,1,3-benzothiadiazol-4-yl]-5,14-dithiapentacyclo[10.6.0.03,10.04,8.013,17]octadeca-1(12),2,4(8),6,10,13(17),15-heptaen-6-yl]-2,1,3-benzothiadiazol-7-yl]methylidene]-1,3-thiazolidin-4-one. InChIKey: HKJHYTKBDDVGRK-IOUDQCQMSA-N.
| Molecular formula | C72H88N6O2S8 |
|---|---|
| Molecular weight | 1326.0 g/mol |
| IUPAC name | (5Z)-3-ethyl-2-sulfanylidene-5-[[4-[9,9,18,18-tetrakis(2-ethylhexyl)-15-[7-[(Z)-(3-ethyl-4-oxo-2-sulfanylidene-1,3-thiazolidin-5-ylidene)methyl]-2,1,3-benzothiadiazol-4-yl]-5,14-dithiapentacyclo[10.6.0.03,10.04,8.013,17]octadeca-1(12),2,4(8),6,10,13(17),15-heptaen-6-yl]-2,1,3-benzothiadiazol-7-yl]methylidene]-1,3-thiazolidin-4-one |
| InChIKey | HKJHYTKBDDVGRK-IOUDQCQMSA-N |
| SMILES | CCCCC(CC)CC1(C2=CC3=C(C=C2C4=C1C=C(S4)C5=CC=C(C6=NSN=C56)/C=C\7/C(=O)N(C(=S)S7)CC)C(C8=C3SC(=C8)C9=CC=C(C1=NSN=C91)/C=C\1/C(=O)N(C(=S)S1)CC)(CC(CC)CCCC)CC(CC)CCCC)CC(CC)CCCC |
Computed by PubChem (NCBI)