cas: 1416773-22-2 — see every product listed under this CAS number, including other names
Rifampicin Impurity 10 (CAS 1416773-22-2) is a chemical reagent available from Chemat. Available pack sizes: 10mg, 25mg, 50mg, 100mg, 200mg. Offered by: Hubei YoungXin.
| brand | Hubei YoungXin |
|---|---|
| catalog number | 940010R-10mg |
| cas | 1416773-22-2 |
| size | 10mg |
| availability | Do potwierdzenia przez Chemat|To be confirmed by Chemat |
Ask us about this product — we're happy to help.
| brand | size | price | |
|---|---|---|---|
| Hubei YoungXin | 10mg | price on request | |
| Hubei YoungXin | 25mg | price on request | |
| Hubei YoungXin | 50mg | price on request | |
| Hubei YoungXin | 100mg | price on request | |
| Hubei YoungXin | 200mg | price on request |
| purity | No data |
|---|---|
| delivery time | To be confirmed by Chemat |
[(7R,9E,11R,12S,13R,14R,15S,16R,17S,18R,19E,21E)-2,13,15,27,29-pentahydroxy-11-methoxy-3,7,12,14,16,18,22-heptamethyl-26-[(E)-(4-methylpiperazin-1-yl)iminomethyl]-6,23-dioxo-8,30-dioxa-24-azatetracyclo[23.3.1.14,7.05,28]triaconta-1(29),2,4,9,19,21,25,27-octaen-17-yl] acetate (CAS 1416773-22-2) is a chemical compound with the molecular formula C43H58N4O12 and a molecular weight of 822.9 g/mol. IUPAC name: [(7R,9E,11R,12S,13R,14R,15S,16R,17S,18R,19E,21E)-2,13,15,27,29-pentahydroxy-11-methoxy-3,7,12,14,16,18,22-heptamethyl-26-[(E)-(4-methylpiperazin-1-yl)iminomethyl]-6,23-dioxo-8,30-dioxa-24-azatetracyclo[23.3.1.14,7.05,28]triaconta-1(29),2,4,9,19,21,25,27-octaen-17-yl] acetate. InChIKey: GMPRCJHFVWRAND-GKFDBJHDSA-N.
| Molecular formula | C43H58N4O12 |
|---|---|
| Molecular weight | 822.9 g/mol |
| IUPAC name | [(7R,9E,11R,12S,13R,14R,15S,16R,17S,18R,19E,21E)-2,13,15,27,29-pentahydroxy-11-methoxy-3,7,12,14,16,18,22-heptamethyl-26-[(E)-(4-methylpiperazin-1-yl)iminomethyl]-6,23-dioxo-8,30-dioxa-24-azatetracyclo[23.3.1.14,7.05,28]triaconta-1(29),2,4,9,19,21,25,27-octaen-17-yl] acetate |
| InChIKey | GMPRCJHFVWRAND-GKFDBJHDSA-N |
| SMILES | C[C@@H]1/C=C/C=C(/C(=O)NC2=C(C(=C3C(=C2O)C(=C(C4=C3C(=O)[C@@](O4)(O/C=C/[C@H]([C@H]([C@@H]([C@H]([C@@H]([C@H]([C@H]1OC(=O)C)C)O)C)O)C)OC)C)C)O)O)/C=N/N5CCN(CC5)C)\C |
Computed by PubChem (NCBI)